Turnout speed..........

[CShaveRR]

I was always told that you doubled the turnout number to get the safe speed.

UP has installed some #30s, with movable frogs, which have three switch machines each: one for the frog and two for the points. If you have to hand-throw both switches of a crossover (which would be thousands of feet apart, with the wide track spacing), that's quite a bit of walking!

I also seem to remember about some new point profile that's supposed to make things safer. How do that, and the movable frogs, affect the speed, if at all?

[kenneo]

QUOTE: Originally posted by mudchicken

Kenneo- carefull, speed is a function of radius/degree of cv. and elevation, switches for the the most part are flat...plus unbalance (in relation to centripital force)

SPEED= SQRT((E+3)/0.0007D) E=0, (flat) D=degree of curvature, 3" maximum unbalance (freight railroads use 2 or less)

Mookie's closed book/open mind pop quiz to follow.......

The proper tem for "Y" switch is equilateral turnout, and they are a relatively minority item whose geometry precludes it from many locations.

You are correct on all points, but if I had tried to explain all of that just to say that you can (within the confines of the physicis involved) double the speed with an equilateral, I would still be writing the post!

Such arrangements as I mentioned are in use on high speed lines, and yes, you can not get double the speed, but, depending on your equipment, can approach that number.

I'm talking "ball park" here. The turnout curvature for a say, #20 E is "1/2" the turnout curvature of a # 20 R or a #20 L, even though the total frog angle is the same, because instead of turning to just one side, you turn to both and "1/2" of the "curvature" is present for each side, and therefor, you have "1/2" of the frog angle. The only practical general use is in high speed rail corriders.

If I were to design something like I am talking about, and did not use the proper engineering formuli, I would indeed have the train in a heap in the middle of the track.

[kenneo]

QUOTE: Originally posted by mudchicken

Kenneo- carefull, speed is a function of radius/degree of cv. and elevation, switches for the the most part are flat...plus unbalance (in relation to centripital force)

SPEED= SQRT((E+3)/0.0007D) E=0, (flat) D=degree of curvature, 3" maximum unbalance (freight railroads use 2 or less)

Mookie's closed book/open mind pop quiz to follow.......

The proper tem for "Y" switch is equilateral turnout, and they are a relatively minority item whose geometry precludes it from many locations.

You are correct on all points, but if I had tried to explain all of that just to say that you can (within the confines of the physicis involved) double the speed with an equilateral, I would still be writing the post!

Such arrangements as I mentioned are in use on high speed lines, and yes, you can not get double the speed, but, depending on your equipment, can approach that number.

I'm talking "ball park" here. The turnout curvature for a say, #20 E is "1/2" the turnout curvature of a # 20 R or a #20 L, even though the total frog angle is the same, because instead of turning to just one side, you turn to both and "1/2" of the "curvature" is present for each side, and therefor, you have "1/2" of the frog angle. The only practical general use is in high speed rail corriders.

If I were to design something like I am talking about, and did not use the proper engineering formuli, I would indeed have the train in a heap in the middle of the track.

[mudchicken]

Kenneo- carefull, speed is a function of radius/degree of cv. and elevation, switches for the the most part are flat...plus unbalance (in relation to centripital force)

SPEED= SQRT((E+3)/0.0007D) E=0, (flat) D=degree of curvature, 3" maximum unbalance (freight railroads use 2 or less)

Mookie's closed book/open mind pop quiz to follow.......

The proper tem for "Y" switch is equilateral turnout, and they are a relatively minority item whose geometry precludes it from many locations.

[mudchicken]

Kenneo- carefull, speed is a function of radius/degree of cv. and elevation, switches for the the most part are flat...plus unbalance (in relation to centripital force)

SPEED= SQRT((E+3)/0.0007D) E=0, (flat) D=degree of curvature, 3" maximum unbalance (freight railroads use 2 or less)

Mookie's closed book/open mind pop quiz to follow.......

The proper tem for "Y" switch is equilateral turnout, and they are a relatively minority item whose geometry precludes it from many locations.

[Anonymous]

QUOTE: In this country, a #20 turnout is good for 40-45mph and a #24 is good for 50 MPH. If you have a train going 100 mph through a #20 lined for the siding, I'm outta here. Nikes don't fail me now!

Well, it's hard to judge the # when you are level with it, it was a huge turnout though.

[Anonymous]

QUOTE: In this country, a #20 turnout is good for 40-45mph and a #24 is good for 50 MPH. If you have a train going 100 mph through a #20 lined for the siding, I'm outta here. Nikes don't fail me now!

Well, it's hard to judge the # when you are level with it, it was a huge turnout though.

[kenneo]

Those speeds are for standard design turnouts. The Normal position being the straight rail and the reverse position curving away.


Now, if you have a number "n" Y Switch, each rout diverges at 1/2 half the curvature of the standard design and the speed can double.

[kenneo]

Those speeds are for standard design turnouts. The Normal position being the straight rail and the reverse position curving away.


Now, if you have a number "n" Y Switch, each rout diverges at 1/2 half the curvature of the standard design and the speed can double.

[Anonymous]

Thanks all.

[Anonymous]

Thanks all.

[mudchicken]

In this country, a #20 turnout is good for 40-45mph and a #24 is good for 50 MPH. If you have a train going 100 mph through a #20 lined for the siding, I'm outta here. Nikes don't fail me now!

#6.5 Turnout = 5-10 mph
#8 Turnout = 10 mph
#10 Turnout =15 mph
#14 Turnout =30 mph
#20 Turnout = 40 mph
#24 Turnout =50 mph

[mudchicken]

In this country, a #20 turnout is good for 40-45mph and a #24 is good for 50 MPH. If you have a train going 100 mph through a #20 lined for the siding, I'm outta here. Nikes don't fail me now!

#6.5 Turnout = 5-10 mph
#8 Turnout = 10 mph
#10 Turnout =15 mph
#14 Turnout =30 mph
#20 Turnout = 40 mph
#24 Turnout =50 mph

[Anonymous]

It really depends on what speed the turnouts are designed for.

Some in Britain are designed for trains to take the diverging route at 100+ mp/h, they are like #20's or some such, huge long things.

[Anonymous]

It really depends on what speed the turnouts are designed for.

Some in Britain are designed for trains to take the diverging route at 100+ mp/h, they are like #20's or some such, huge long things.

[Anonymous]

Just wondering.......... Taking a turnout at speed sometimes raises havoc in the dinning car. I have seen meals dumped on passengers and myself been thrown against a wall and brused. I guess that is the price we pay to enjoy our hobby. Artisimm5 [:)]

[Anonymous]

Just wondering.......... Taking a turnout at speed sometimes raises havoc in the dinning car. I have seen meals dumped on passengers and myself been thrown against a wall and brused. I guess that is the price we pay to enjoy our hobby. Artisimm5 [:)]