Owner and superintendant of the N scale Texas Colorado & Western Railway, a protolanced representaion of the BNSF from Fort Worth, TX through Wichita Falls TX and into Colorado.
Check out the TC&WRy on at https://www.facebook.com/TCWRy
Check out my MRR How-To YouTube channel at https://www.youtube.com/c/RonsTrainsNThings
Joe Fugate Modeling the 1980s SP Siskiyou Line in southern Oregon
QUOTE: Originally posted by electrolove Joe: Thanks for the great clinic. One question for you. Whalthers/Shinohara DCC friendly turnouts, can they be used right out of the box without problems?
QUOTE: Originally posted by jfugate QUOTE: Originally posted by electrolove Joe: Thanks for the great clinic. One question for you. Whalthers/Shinohara DCC friendly turnouts, can they be used right out of the box without problems? Yes, that's the beauty of all the DCC friendly turnouts listed. You just install them, solder track feeders to the stock rails, and you're done.
QUOTE: Originally posted by jfugate Ron: Yes, that would work, assuming there is only one track feeder to the train block, and it has an 1156 bulb in it.
Modeling the Reading Railroad in the 1950's
Visit my web site at www.readingeastpenn.com for construction updates, DCC Info, and more.
QUOTE: Originally posted by Bullitt406 What about Atlas Custom Line versus Super Switch. Any difference between those other than appearance? Josh
QUOTE: Originally posted by selector Randy, or Joe ( or an electrical engineer who is reading), I understand Randy's response, and it makes sense. Just for my edification, is there an exponential relationship involved? I ask this because the light bulb will be drawing current all the while if it is ever going to draw current. So, is the draw inversely proportional to ....what, resistance? Help me to appreciate what the bulb is doing when it is not protecting the booster and locos during normal running.
QUOTE: Originally posted by rrinker QUOTE: Originally posted by selector Randy, or Joe ( or an electrical engineer who is reading), I understand Randy's response, and it makes sense. Just for my edification, is there an exponential relationship involved? I ask this because the light bulb will be drawing current all the while if it is ever going to draw current. So, is the draw inversely proportional to ....what, resistance? Help me to appreciate what the bulb is doing when it is not protecting the booster and locos during normal running. Acting like a resistor, a low value one. There are devices called Negative Temperature Coefficient Resistors (NTC) that would work the same as the light bulbs, if the proper values can be found. But they cost more than 1156 bulbs. --Randy
QUOTE: Originally posted by rrinker Exactly. When there is no train in the block, the lights do nothing. The unoccupied track is an open circuit.
Simon Modelling CB&Q and Wabash See my slowly evolving layout on my picturetrail site http://www.picturetrail.com/simontrains and our videos at http://www.youtube.com/user/MrCrispybake?feature=mhum