ROBERT PETRICK
Based on the angles you gave (7.15 degrees and 172.85 degrees) and the length projected onto the x-axis (98"), there would be four sides, each 49.19" long. The 9" height does not fit. (actually 6.12")
Holding the 98" projected length and the 9" offset, then the angles become 10.49 degrees and 169.51 degrees and the four sides become 49.41" long.
Robert, I know you did what it sounded like he was explaining, but that is not what he is looking for.
He does not mean the x-axis thru the rhombus.
He means draw a rhombus using the angles he indicated, a long skinny rhombus where the two horizontal sides are 9" apart.
The left and right sides of the rhombus will become the "C" side of a right triangle scribed inside or outside the tip of the rhombus.
That triangle "A" side, plus length of the horizontal side of the rhombus = 98"
How long is horizontal side of the rhombus? How long is the left/right side of the rhombus?
What I want to know is why 9"?
If I was laying out track I would be using center lines on 2" centers so the width would be an even number. OR, if I wanted to map the space that would be used it would sill be an even number, 2" "spsce" for each track.
But to answer the question, the horizontal sides would be 26.2542" long, the angled sides sloping up from horizontal at 7.15 degrees would be 72.3080" long.
I would draw a picture, but I don't really know how to do that quickly on here.
Sheldon