QUOTE: Originally posted by Virginian Further consideration - the pistons in an automotive engine work the same basic way
QUOTE: Originally posted by selector The bumpers do not meet until the couplers are essentially compressed, otherwise the cars could not be shunted in tight turns in yards. If they could be at significant angles to each other, the bumpers would get in the way. So, there must be a gap, and that gap affords the sequential starting described earlier.
Five out of four people have trouble with fractions. -AnonymousThree may keep a secret, if two of them are dead. -Benjamin Franklin "You don't have to be Jeeves to love butlers, but it helps." (Followers of Levi's Real Jewish Rye will get this one) -Ed K "A potted watch never boils." -Ed Kowal If it's not fun, why do it ? -Ben & Jerry
-Dan
Builder of Bowser steam! Railimages Site
QUOTE: Originally posted by Roger Traviss Keep in mind that NO locomotive ever moves the whole train at one time. When a locomotive starts, it picks up one car at a time and that car adds its inertia to the movement which adds a small amount to assist moving the next car and so on
Mark P.
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QUOTE: Originally posted by edkowal The rolling resistance of a modern freight car on roller bearing trucks is only about 1% of the dead weight of the car. It takes a lot less force than you would think to keep it moving on level track. If you follow that first statement, it means that the force required to keep a 100 car freight train moving is only equal to the weight of ONE of its cars!! -Ed
QUOTE: Originally posted by Brunton Either the formula or the definition of the terms is inaccuate. One of the things directly affecting Tractive Effort is the ratio of the (offset of the Side Rods from the wheel axles) to the (wheel diameter). Maybe D in the equation above takes this into account, but then D wouldn't be the actual wheel diameter.
QUOTE: Originally posted by edkowal The formula: Tractive Effort = ( c P d d s ) / D where c = constant mentioned above P = boiler pressure d = piston diameter s = piston stroke D = wheel diameter
QUOTE: Originally posted by GBeylick I've wondered these many decades just how steam generated by a locamotive has the power to push against a piston of a steam engine to which a hundred or more cars are attached.Huge steam pressure has to build inside the cylinder...So why then doean't the ends of the cylinders blow off?
QUOTE: Originally posted by GBeylick [Huge steam pressure has to build inside the cylinder with the piston fighting against the weight of the locomotive and its rolling stockl. So why then doean't the ends of the cylinders blow off? Just what gives the locomotive a boost to get its wheels moving ,and its strength to pull mile-long rolling stock?