I need to have the wire connection for the enclosed photo Thanks Harold
I need to have the wire connection for the enclosed photo
Thanks
Harold
So those are LEDs, or are they bulbs?
A single-pole/single-throw (SPST) switch has 2 connections. Your drawing suggests a single-pole/double-throw (SPDT) switch which makes a connections between a common terminal and one of the other two.
the two bulbs, a single resistor and SPDT switch suggests that you want to the switch to turn on one or of the two lamps.
why is there a resistor? An incandecent bulb is normally connected to power at the voltage the bulb is rated at. Do you mean LED instead of bulb? Connect the anode end of an LED to the switch.
V+ --o --o --- bulb ------ resistor ---- Gnd \--o --- bulb --|connect the common terminal of the switch to power.connect each of the other two switch terminals to one lead of each bulbconnect the other lead of each bulb together and to the resistor.connect the other resistor lead to groundthe switch provides power on bulb or the other
greg - Philadelphia & Reading / Reading
These are LED's.
The switch turn one light on if you throw to the left and turns on the other light if you throw to the right.
left
Short lead of one LED to the left pin of the switch. Short lead of other LED to the right pin of the switch. Resistor to the middle pin. Other side of resistor to power supply -, the two free longer leads of the LEDs to the poswer supply +.
Just flip the LED on the right in your picture and the leads line up exactly where they need to connect.
--Randy
Modeling the Reading Railroad in the 1950's
Visit my web site at www.readingeastpenn.com for construction updates, DCC Info, and more.
Randy
I forgot. 12vdc or 18vac
12V DC. What value resistor do you have? 1K is probably good.
hwolf Randy I forgot. 12vdc or 18vac Harold
As Randy said, 1k is good for 12 vdc and allows about 10 ma of currecnt.
If you used 18 vac, 1.8 k would allow about the same current.
Some suggest a protective diode when using AC.
Ohm's law calculator.
https://www.digikey.com/en/resources/conversion-calculators/conversion-calculator-ohms?&WT.srch=1&gclid=CL_B876J1dMCFdQ9gQodUkgOsw
Rich
If you ever fall over in public, pick yourself up and say “sorry it’s been a while since I inhabited a body.” And just walk away.
Thanks Randy
It is a 1K.
Ok Now we have another problem.
All wiring is per your post and all solder joint are tight. When I throw the switch to the left the green light goes on as it is supposed to. When I throw the switch to the right the red Led does not light.
What reading should I get on my meter set to DC and using the drawing above where should I place the leads from the meter
The power supply lead on one side of the resistor is 9.89v and on the other side of the resistor is 1.84v
rrinker Short lead of one LED to the left pin of the switch. Short lead of other LED to the right pin of the switch. Resistor to the middle pin.
are you sure the middle pin is the common?
I believe Randy described wiring the circuit as below
|--- LED ---o (A) | \V+ --| o--- resistor ---- Gnd | . |--- LED ---o (B)check the voltage between the LED/Switch (A/B) connections and ground. When the LED is on, there should be a small voltage and a higher voltage when the LED is off. If the LED is off and there is no voltage, the LED may be backwards.it's also possible the switch is miswired, an LED is connected to the common terminal instead of the resistor (shown below).
|--- LED ---o (A) | | .V+ --| | o--- resistor ---- Gnd | | |--- LED ---o (B)
With the circuit unpowered, measure the resistance between the terminal connected to the resistor and the other two terminals. Depending on the switch position, one or the other should be low resistance.
rrinkerJust flip the LED on the right in your picture and the leads line up exactly where they need to connect.
Did you remember to that?
Henry
COB Potomac & Northern
Shenandoah Valley
Be one of the first SPDT toggles I've seen where the middle wasn't the common. I suspect polarity is just reversed on the red LED.