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turnout angle and crossing degrees question

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  • From: Colorful Colorado
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Posted by Texas Zepher on Monday, October 16, 2006 10:01 PM
 kchronister wrote:
It's a custom-line I was talking about. The #6 is too, if that alters anything...
According to my Atlas reference a custom line #6 is a ten (10) degree departure, which means it is slightly tighter than a strict #6.   I don't have any information on their super-track #6.
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Posted by Anonymous on Monday, October 16, 2006 4:29 PM
No sweat, I appreciate the help! Cool [8D]
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Posted by Gary UK on Monday, October 16, 2006 3:56 PM
 kchronister wrote:

Yes, Gary. Thanks very much!

I meant literally find it. The Walthers/Shinohara diamond sounds great... Finding someone with it in stock, now that's the trick... I am finding a Peco #6 diamond crossing, however, that might serve well.

Kris

 

Ah, sorry bud, i misunderstoodSmile [:)]

 

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Posted by Anonymous on Monday, October 16, 2006 3:46 PM

Yes, Gary. Thanks very much!

I meant literally find it. The Walthers/Shinohara diamond sounds great... Finding someone with it in stock, now that's the trick... I am finding a Peco #6 diamond crossing, however, that might serve well.

Kris

 

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Posted by Gary UK on Monday, October 16, 2006 2:44 PM
 kchronister wrote:
[

Now I just have to go find a 9.5-degree code 83 diamond...

 

Errr, i just told you aboveBig Smile [:D]

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Posted by Anonymous on Monday, October 16, 2006 2:14 PM
 Texas Zepher wrote:

 kchronister wrote:
I use min #6 on my mainline... Does anyone know what degrees of crossing that would require? And maybe where to get one (handlaying not being my bag)...?

opposite/adjacent = 1/6 = 0.1666,  Arctangent(0.1666) = 0.1655 radians or  9.46 degrees.

So a 10 degree crossing could probably be fudged in.

P.S. I get 14 degrees for a true number 4 turnout.  12.5 degrees is for a #4.5 turnout like the Atlas custom line.

Nailed it, TZ. It's a custom-line I was talking about. The #6 is too, if that alters anything...

Now I just have to go find a 9.5-degree code 83 diamond...

 

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Posted by Texas Zepher on Monday, October 16, 2006 2:07 PM

 kchronister wrote:
I use min #6 on my mainline... Does anyone know what degrees of crossing that would require? And maybe where to get one (handlaying not being my bag)...?

opposite/adjacent = 1/6 = 0.1666,  Arctangent(0.1666) = 0.1655 radians or  9.46 degrees.

So a 10 degree crossing could probably be fudged in.

P.S. I get 14 degrees for a true number 4 turnout.  12.5 degrees is for a #4.5 turnout like the Atlas custom line.

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Posted by Gary UK on Monday, October 16, 2006 1:36 PM

Im pressuming then, you want a diamond crossing to go across the right hand mainline.

The frog of the diamond will be the same angle as the frog on your right hand switch. The Walthers Shinohara #6 has a frog angle of 9.30 degrees but unfortunately they dont make a #6 diamond. Not that ive seen anyway! However, Peco do (in code 83 and 100 rail) make a #6 switch aswel as a #6 diamond. This would give you your required angles without any alignment problems.

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turnout angle and crossing degrees question
Posted by Anonymous on Monday, October 16, 2006 12:05 PM

Okay, imagine I am on the left-hand track of a two-track main. I want to have a turnout to the right, a crossing over - but not connecting to as with a turnout - the other parallel track, and then continuing on of course.

I know that if I use a #4 right turnout and a 12.5 degree crossing, I can get all the angles lined up right.

However, I use min #6 on my mainline... Does anyone know what degrees of crossing that would require? And maybe where to get one (handlaying not being my bag)...?

Thanks,

Kris

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