Hi palmland
Start by geting the right caboose industries ground throw with the right contacts, that is also your electrical switch.
Get a bulk bag of yellow LED's it will be cheaper than Bi or Tri colour LED's
On your panel lay out to represent the switch yellow LED's in a triangle, one for main line one for siding one where the toe of the blades is.
Wire the blade toe LED so it is perminatly lit wire the other two so when the ground throw is throw the LED for that track lights up and the other track one goes out. you have a clear unmistakeable Two LED indication of which track the switch is set for.
Wired correctly the LED triangle will show the direction points are set and that the polarity has changed to suit idealy you want both to change at the same time.
Do not forget the resistors or the LED'S will blow.
Hopefully some one a bit more knowledgable can draw an easy to follow diagram from my description.
regards John
[quote user="hucomp"]
This is very helpful as I am trying to do exactly this! But the instruction are for electrofrog turnouts. To do the same for insulfrog turnouts you need to attach wires to both point rails then join them together with the common wire on the LED (3 wires now running to the resistor and the common LED wire) and you're in business. You will have to test the light to see which wire goes where but it does work! This can also be done with installed turnouts by running the necessary wires up through the baseboard and soldering them to the specific rails (this is what I had to do.)
Cheers
I haven't tried this, but it should work:
Use a bi-color LED. These have 3 leads, common, red and green. (They do make them in other colors, but those are the most common for MR use.) Connect the common lead to a 1K resistor, and then connect the resistor to the frog. Connect the red lead to one outside rail of the turnout, and the green lead to the other outside rail. When the turnout is thrown in the "straight" position, the frog power will be the same as the "curved" outside rail, so current will flow through one side of the LED. When you throw the turnout to the "curved" position, the frog polarity will flip and current will flow through the other side of the LED.
This works in DCC because the voltage on the track is a modulated square wave, which looks kind of like AC to the LED. The diode character of the LED acts like a half-wave rectifier, but it's fast enough that the LED will actually turn on and off much more rapidly than your eye can see.
It takes an iron man to play with a toy iron horse.
YOU MUST HAVE A RESISTOR in the circut or POP goes the LED. The Tortise is the resistor.
Alternate plan "B" is GRAIN OF RICE bulbs from Micro Mark. They take full line voltage and work very well. They like a resistor also but work well without one.
-Dan
Builder of Bowser steam! Railimages Site