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Helix Grade

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Helix Grade
Posted by jpdriver on Sunday, October 20, 2019 6:50 PM

I am looking for some feedback from those whom have already either succeeded or struggled with a helix. I am trying to go as tight as I can and still have a reliable helix. I am looking at my outside track on a double helix. The inside will be downhill and will be 1.25" shorter in radius than the outside. I need a little room on the outside of the helix for additional tracks to run around to different branches. My struggle in the decision process is the grade. I am looking at either a 2.59 percent or a 2.79 percent depending on the outside uphill radius of either 16.25" or 17.5". The 16.25" does not seem like much smaller, but gains me 3.5" in the overall circumference. I model mid 1980s and do not run cars any longer than 50' prototypical pulled by 2 or 3 SD motors. Looking for thoughts on the grade, expected numbers of cars that can be pulled on the grade, etc. from a few helix users.

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Posted by Steven Otte on Monday, October 21, 2019 8:39 AM

The scale you're modeling in would be important to know. From the radius we can assume N scale, but, better to know for sure before we offer advice.

--
Steven Otte, Model Railroader senior associate editor
sotte@kalmbach.com

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Posted by York1 on Monday, October 21, 2019 8:47 AM

I don't know about the answers to your questions, but welcome to the forum!

York1 John       

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Posted by SeeYou190 on Monday, October 21, 2019 8:50 AM

Welcome to the Model Railroader forums. Your first few posts are delayed by the moderators, but that ends soon enough.

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I am going to assume you are in N scale. That is the only scale I have built a helix for.

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My best advice is make it as big as possible and use Kato Unitrack for all hidden trackage. The one I built like this was completely trouble free.

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-Kevin

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Living the dream.

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Posted by RR_Mel on Monday, October 21, 2019 9:18 AM

I built a helix on my HO 14’ x 10’ layout that has a 3½% grade.  The radius is 30” and a pair of diesels will pull 10 over weighted passenger cars up it easily.  A single Cab Forward (8 ounces of added weight) struggles (slight wheel slip) with the same 10 cars.
 
My normal direction for the helix is down hill so it’s not a problem.  The up side of the grade has two 34” radius curves with the same 3½% grade and my Cab Forward pulls that grade easily without any wheel slip.
 
 
Mel
 
 
My Model Railroad   
 
Bakersfield, California
 
I'm beginning to realize that aging is not for wimps.
 
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Posted by gregc on Monday, October 21, 2019 9:54 AM

jpdriver
Looking for thoughts on the grade,

should consider the Effective Slope caused by curves, http://cs.trains.com/mrr/f/11/t/221186.aspx

 

jpdriver
expected numbers of cars that can be pulled on the grade,

that really depends on the weight of the locos pulling the cars.

greg - Philadelphia & Reading / Reading

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Posted by selector on Monday, October 21, 2019 3:18 PM

...and also the weights and free-rolling characteristics of the trailing cars. Even mismatched couplers can cause grief in hidden trackage.  Oh, and how skilled are you at laying a consistent grade?

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Posted by jpdriver on Monday, October 21, 2019 4:07 PM

Sorry, I left off...yes this is N-scale. I am confident in being able to create a consistent grade. I do a lot of carpentry and have good tools. I also plan to use a commercially available radius track to ensure I do not vary my radius with flex track at all.

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Posted by gregc on Monday, October 21, 2019 4:30 PM

selector
how skilled are you at laying a consistent grade?

how consistent does it really need to be?

if part of the train is on slightly steeper and another part on a slightly lesser grade, doesn't it average out?

isn't what really matters the change in height over the length of the train?

greg - Philadelphia & Reading / Reading

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Posted by rrinker on Monday, October 21, 2019 6:16 PM

 I'll say the same thign I always say about helix building - I see so many people anguish over making a consistent grade, and using all sorts of contraptions to achieve adjustability. Why? The critical parts are the first turn, where you transition from flat to whatever grade the helix will be, and the last loop, where you have to transistion from a grade back to flat. Once you have the first loop set - every spacer between levels is exactly the same length, no matter how many of them you have aroudn each turn! Set a stop on a chop saw and turn them out by the dozens. There's no need for threaded rods with brackets or such contraptions. See the MRVP video on buildign the helix in the Canadian Canyons layout. 

                            --Randy

 


Modeling the Reading Railroad in the 1950's

 

Visit my web site at www.readingeastpenn.com for construction updates, DCC Info, and more.

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Posted by selector on Monday, October 21, 2019 11:26 PM

All my engines slow noticeably when the grade steepens. So, if you have one pretty close to its limit for trailing ‘tonnage’ on a 3% grade and have a two foot section at 3.5%, you stand what to me would be an unacceptable probability of a stall. Works just like that in the prototype as well.

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Posted by davidmurray on Wednesday, October 23, 2019 9:58 AM

selector
All my engines slow noticeably when the grade steepens. So, if you have one pretty close to its limit for trailing ‘tonnage’ on a 3% grade and have a two foot section at 3.5%, you stand what to me would be an unacceptable probability of a stall. Works just like that in the prototype as well.

Rrinker seems to address this.  One more stack of blocks under the sagging section, and the problem will be solved.

Dave

 

David Murray from Oshawa, Ontario Canada
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Posted by selector on Wednesday, October 23, 2019 3:18 PM

That’s all fine, providing one uses that method. Many don’t, or won’t, or can’t. I merely brought up the caution that it is a potential pitfall. Bang Head

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Posted by jpdriver on Wednesday, October 23, 2019 3:24 PM

Thanks for the thoughts guys. Being one that wants to get this right the first time, I redesigned and grew the uphill helix to a 20" radius which will allow me to also reduce the grade a bit more. This should overcome my fear of being stuck with a grade not able to be overcome with a 15-20 car train.

 

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Posted by Pruitt on Wednesday, October 23, 2019 6:51 PM

Your effective, or compensated, grade is determined by this formula:

CG=G+28/R

So you will see an effective grade of 2.4% + 28/20, or 3.8%

This is based on an elevation change of 3" per turn, which I calculated from the numbers given in your initial post.

Depending on the number and length of the cars you'll be pulling, stringlining could become an issue (but with that radius in N scale, probably not).

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Posted by rrinker on Wednesday, October 23, 2019 7:03 PM

 You forgot to adjust the compensation factor for scale. About 17.5 for N scale, per Byron Henderson, so it's more like 2.4% + 17.5/20, or 2.4% + .875 = a bit under 3.3% effective grade.

 The 3" elevation change is going to be tight - PLENTY of celarance for N scale equipment, and the roadbed of the helix (unless making it out of 3/4" plywood or something), but getting a hand in there to fix something is going to be tough. But to provide ample clearance will require a much larger radius to keep the grade manageable. 

                     --Randy

 


Modeling the Reading Railroad in the 1950's

 

Visit my web site at www.readingeastpenn.com for construction updates, DCC Info, and more.

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