upchuck wrote:to prevent either car from moving?
By they time you did the above calculations, the car would already be out the other end...
Although if you take the static coefficient, applied it to a surface with a specific gravity of 1G, dividing by the reflective coefficient of the Coriollis effect, allowing for centrifugal forces interference with centripidal forces, adding wind speed, and taking the perihelion of the relative position of Jupiter and the Sun, and assuming that there are no gravitational anomolies within a geometric area equal to 1/2 the surface area exposed to air, then factoring in the average speed of an European Swallow (not carrying any coconuts), I calculate that you would need 494,322 egrs of energy (translated into 4,377,890 Newtons of force, [but only if you are using Fig Newtons]).
rrnut282 wrote:A little more information is needed. Is the track flat? What is the vector of the wind (in reference to track centerline) and and what is the cross-sectional area of the car ends? Otherwise, if the track is flat and there is no wind, there is no force(s) to counteract and the friction needed is zero.
upchuck wrote:Two boxcars sit on a railroad track. Boxcar B has mass 3.00 × 105 kg and its center is 25.0 m, 0.0° from the center of boxcar A, which has mass 4.50 × 105 kg. (a) Determine the acceleration of each boxcar assuming there is no friction. (b) What is the minimum coefficient of static friction in order to prevent either car from moving?
Chuck-
You left something out. You need an applied force in order to solve this.
BTW, I think you should do your own Physics homework!
-Don (Random stuff, mostly about trains - what else? http://blerfblog.blogspot.com/)
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Carl
Railroader Emeritus (practiced railroading for 46 years--and in 2010 I finally got it right!)
CAACSCOCOM--I don't want to behave improperly, so I just won't behave at all. (SM)
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