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[quote user="Murphy Siding"] If the number of accidents and injuries held steady, but the percentages went up because of 11% fewer employees and less trains, shouldn't the 14% figure and 19% figure be relatively the same % number? With less employees and less trains, why didn't the % go down?[/quote] To get the accident rate you divide the number of accidents by the number of trains. With the number of accidents steady but less trains the denominator gets smaller and the percentage gets higher. The given percentages of 14% and 19% are not the accident rates but their percental change: x number accidents, n number trains. accident rate: x/n; with 10% less trains x/(0.9*n); difference: x/(0.9*n)- x/n = 0.1*x/0.9*n percental change: (0.1*x/0.9*n)/(x/n)*100 = change [%] = 0.1/0.9*100= 11.1% So a reduction of train number by 10% with steady accident numbers leads to an increase of the accident rate by 11.1%. I hope that helps a bit. If I made a mistake please correct me, it is quite some time since I retired. Regards, Volker
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