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Wiring a Helix for DCC
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<p>[quote user="gregc"]</p> <p>so how much overkill is necessary?</p> <p> </p> <div class="quote-header"> </div> <blockquote class="quote"> <div class="quote-user">BMMECNYC</div> <div class="quote-content">Also this: <p><a href="https://sites.google.com/site/markgurries/home/dcc-general-best-practices/wiring-planing">https://sites.google.com/site/markgurries/home/dcc-general-best-practices/wiring-planing</a></p> </div> </blockquote> <div class="quote-footer"> </div> <p> </p> <div style="clear:both;"> </div> <p>[/quote]</p> <p><a href="https://sites.google.com/site/markgurries/home/dcc-general-best-practices/track-feeders-frogs/soldered-railjoiners-and-feeders">https://sites.google.com/site/markgurries/home/dcc-general-best-practices/track-feeders-frogs/soldered-railjoiners-and-feeders</a></p> <p>This says every piece of flex track or every other if the railjoiners on both sides are soldered.</p> <p>So three pieces of flex track has two feeders. If you solder one near the beginning of one piece of flex track and the other near the end of the third, that comes out to about every 8-9 feet you have a feeder. Or more clearly stated, two per loop of helix the previously described 17' circumference helix.</p> <p> </p>
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