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<p>[quote user="gregc"]</p> <p> </p> <div class="quote-header"> </div> <blockquote class="quote"> <div class="quote-user">BMMECNYC</div> <div class="quote-content">I guess it might be also that there is resistance at each conection that is not accounted for in your calculation (wire to booster, wire to smaller wire, small wire to rail).</div> </blockquote> <div class="quote-footer"> </div> <p> </p> <p>he said the booster outputs 14.2V.    A resistance of 2.84 Ohm results in 5A.</p> <p>if there is 0.61 ohm of resistance in 50 ft of 14g and 12 ft of 26g, you're suggesting that the majority of the resistance is in the connections (2.2 Ohm = 2.8 - 0.6), not in the wire.</p> <div style="clear:both;"> </div> <p>[/quote]</p> <p>And now that I read Randy's response... and Mark Gurries' explanation:</p> <p>The short itself is a resistive load, in addition to all of the above things.  </p> <p>The only thing we have control over at the time of the short is the resistance of the wire that is installed.  The rest (wheel contact, rail cleanliness, locomotive internal wiring) is out of our control.  </p> <p>Which is why people suggest what seems like overkill on wiring and feeders. </p>
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