There is nothing 'scale specific' about calculating a grade. It is simply the rise(unit) in 100 units of length. For example, a 2% grade rises 2" in a run of 100". Your example would go into the equation like this:
(35*100)/952 = 3.67%
(5*100)/132 = 3.78%
Jim
Modeling BNSF and Milwaukee Road in SW Wisconsin
jimsabol wrote:What is an algorithm for figuring--for example--the grade needed to rise 35" in 952" or 5" in 132"? (Talking O scale here) Thanks. NisquallyJim here.
Grade is easier than you might think and works the same for all scales. It's just rise divided by run (use the same units for each).
35" in 952" is nearly 3.7% (35/952). 5" in 132" is nearly 3.8% (5/132). Fairly steep for mainline running and you'll probably want some of that distance at each end for a vertical transition, which makes the remaining grade a bit steeper.
[Edit: Just like Jim B. said while I was typing!]
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