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Scratch building structures to scale......what's the formula?

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Scratch building structures to scale......what's the formula?
Posted by Anonymous on Thursday, January 19, 2006 7:54 AM
Thought I'd start a new thread, didn't want to piggyback on the outdoor building thread.

I'm using 1/29th scale USA and Aristocraft trains. I'm trying to search and locate the size buildings, like the door opening, a figure so it will be to scale.

I was thinking 3 inches tall for a figure? is that right? what is the rule of thumb for making buildings to scale??

thanks

dan
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Posted by Capt Bob Johnson on Thursday, January 19, 2006 8:01 AM
Check out GR mag advertiser --- The Scale Card ---- makes a neat wallet size card that does 99% of it for you!

No, I don't work for them, I just am a user and got a couple of extra to give to friends!
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Posted by Anonymous on Thursday, January 19, 2006 8:15 AM
Great!! Thanks Capt. Bob.......

dan
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Posted by van buren s l on Thursday, January 19, 2006 8:34 AM
Dan
If you want to find out the correct measurements for1/29 you convert whatever you want to build to inches and divide by 29. For instance, if you want to know the correct size for a six foot man you simply divide 72 inches by 29 . Your figure will be a tad under 2 and 1/2 inches. I hope that takes the mystery out of it for you.
Happy modeling.
Bob
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Posted by Tom The Brat on Thursday, January 19, 2006 8:37 AM
In 1:29:

2 inches is just shy of 5 ft (58 inches)
2 1/2 inches is 6ft
A 7 ft door is 2.9 inches.

It's easy to mulitply by 29. Just multiply by 3, tack on a zero and reduce by the multiplier.
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Posted by RhB_HJ on Thursday, January 19, 2006 10:20 AM
Hmmmmmmmm interesting!

If you want to build to scale you take the prototype measurements and divide those by whatever scale ratio you intend to build to.

My "Hmmmmm" refers to the fact that doing the "Metric thing" sure makes life a lot easier. [;)][}:)][:D][:D] Or at least one doesn't end up with "a tad under or over".[;)][:)][:p][:D][:D]
Cheers HJ http://www.rhb-grischun.ca/ http://www.easternmountainmodels.com
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Posted by van buren s l on Thursday, January 19, 2006 11:05 AM
H J
Didn't you know that a tad is the width of the kerf left by a saw with a fine blade? [;)]
Bob
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Posted by RhB_HJ on Thursday, January 19, 2006 11:30 AM
QUOTE: Originally posted by vbsltco

H J
Didn't you know that a tad is the width of the kerf left by a saw with a fine blade? [;)]
Bob


Bob, [;)][;)]

No, I didn't, but I'm willing to learn. [;)][:p][;)][:D]
Cheers HJ http://www.rhb-grischun.ca/ http://www.easternmountainmodels.com
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Posted by Capt Bob Johnson on Thursday, January 19, 2006 3:51 PM
Just a tad over 10 centimeters, but less than 11 cm?

Oh, that's milimeters!

OK HJ, you got me on that one, even if I don't like metrics! I always had trouble figuring out how long a 300 meter ship really was, but 984 feet meant something to me (it's a big sucker!!!!)
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Posted by Tom The Brat on Thursday, January 19, 2006 6:02 PM
I can think in metric or english, just don't mix the two.
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Posted by RhB_HJ on Thursday, January 19, 2006 6:39 PM
QUOTE: Originally posted by Torby

I can think in metric or english, just don't mix the two.


Torby

Have you ever modeled (meddled[}:)][}:)]) in HO? Would you believe that the "official designation" in certain circles is "3.5mm/foot".
Now I won't be pointing any fingers, suffice to say, it wasn't the Europeans who coined that one. [;)][:p][;)][:)][:D][:D]

Cheers HJ http://www.rhb-grischun.ca/ http://www.easternmountainmodels.com
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Posted by Puckdropper on Thursday, January 19, 2006 8:45 PM
I think we Americans need to adopt a measurement like the millimeter and not 1/16ths of an inch. (Shoot, give a name to the sixteenth like say, "hench" (hex inch) and you've got a nice smallish measurement.) I also think the metric folks need a measurement that's about 3 decimeters long.
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Posted by Anonymous on Friday, January 20, 2006 8:06 AM
Whew!!! Ok.....thanks everyone for your input. I believe I can get my buildings to scale now.....!!!

dan
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Posted by Tom The Brat on Friday, January 20, 2006 9:36 AM
Just use a calculator and divide by 29[;)]

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